2(m-15)=-3(3m+10)+m

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Solution for 2(m-15)=-3(3m+10)+m equation: 



2(m-15)=-3(3m+10)+m

We move all terms to the left:

2(m-15)-(-3(3m+10)+m)=0

We multiply parentheses

2m-(-3(3m+10)+m)-30=0



We calculate terms in parentheses: -(-3(3m+10)+m), so:

-3(3m+10)+m

We add all the numbers together, and all the variables

m-3(3m+10)

We multiply parentheses

m-9m-30

We add all the numbers together, and all the variables

-8m-30

Back to the equation:

-(-8m-30)



We get rid of parentheses

2m+8m+30-30=0

We add all the numbers together, and all the variables

10m=0

m=0/10

m=0

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