2(m-2)+6=4(m-1)-3m

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Solution for 2(m-2)+6=4(m-1)-3m equation: 



2(m-2)+6=4(m-1)-3m

We move all terms to the left:

2(m-2)+6-(4(m-1)-3m)=0

We multiply parentheses

2m-(4(m-1)-3m)-4+6=0



We calculate terms in parentheses: -(4(m-1)-3m), so:

4(m-1)-3m

We add all the numbers together, and all the variables

-3m+4(m-1)

We multiply parentheses

-3m+4m-4

We add all the numbers together, and all the variables

m-4

Back to the equation:

-(m-4)



We add all the numbers together, and all the variables

2m-(m-4)+2=0

We get rid of parentheses

2m-m+4+2=0

We add all the numbers together, and all the variables

m+6=0

We move all terms containing m to the left, all other terms to the right

m=-6

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