2(m-2)-(2m+3)+4m=6m+(4m+4)

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Solution for 2(m-2)-(2m+3)+4m=6m+(4m+4) equation: 



2(m-2)-(2m+3)+4m=6m+(4m+4)

We move all terms to the left:

2(m-2)-(2m+3)+4m-(6m+(4m+4))=0

We add all the numbers together, and all the variables

4m+2(m-2)-(2m+3)-(6m+(4m+4))=0

We multiply parentheses

4m+2m-(2m+3)-(6m+(4m+4))-4=0

We get rid of parentheses

4m+2m-2m-(6m+(4m+4))-3-4=0



We calculate terms in parentheses: -(6m+(4m+4)), so:

6m+(4m+4)

We get rid of parentheses

6m+4m+4

We add all the numbers together, and all the variables

10m+4

Back to the equation:

-(10m+4)



We add all the numbers together, and all the variables

4m-(10m+4)-7=0

We get rid of parentheses

4m-10m-4-7=0

We add all the numbers together, and all the variables

-6m-11=0

We move all terms containing m to the left, all other terms to the right

-6m=11

m=11/-6

m=-1+5/6

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