2(m-2)-(2m+3)+4m=6m+(4m+4)

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Solution for 2(m-2)-(2m+3)+4m=6m+(4m+4) equation:



2(m-2)-(2m+3)+4m=6m+(4m+4)
We move all terms to the left:
2(m-2)-(2m+3)+4m-(6m+(4m+4))=0
We add all the numbers together, and all the variables
4m+2(m-2)-(2m+3)-(6m+(4m+4))=0
We multiply parentheses
4m+2m-(2m+3)-(6m+(4m+4))-4=0
We get rid of parentheses
4m+2m-2m-(6m+(4m+4))-3-4=0
We calculate terms in parentheses: -(6m+(4m+4)), so:
6m+(4m+4)
We get rid of parentheses
6m+4m+4
We add all the numbers together, and all the variables
10m+4
Back to the equation:
-(10m+4)
We add all the numbers together, and all the variables
4m-(10m+4)-7=0
We get rid of parentheses
4m-10m-4-7=0
We add all the numbers together, and all the variables
-6m-11=0
We move all terms containing m to the left, all other terms to the right
-6m=11
m=11/-6
m=-1+5/6

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