2(m-2)-3(m-3)=5(m-5)-4(m-8)

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Solution for 2(m-2)-3(m-3)=5(m-5)-4(m-8) equation: 



2(m-2)-3(m-3)=5(m-5)-4(m-8)

We move all terms to the left:

2(m-2)-3(m-3)-(5(m-5)-4(m-8))=0

We multiply parentheses

2m-3m-(5(m-5)-4(m-8))-4+9=0



We calculate terms in parentheses: -(5(m-5)-4(m-8)), so:

5(m-5)-4(m-8)

We multiply parentheses

5m-4m-25+32

We add all the numbers together, and all the variables

m+7

Back to the equation:

-(m+7)



We add all the numbers together, and all the variables

-1m-(m+7)+5=0

We get rid of parentheses

-1m-m-7+5=0

We add all the numbers together, and all the variables

-2m-2=0

We move all terms containing m to the left, all other terms to the right

-2m=2

m=2/-2

m=-1

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