2(m-2)=-5(3-m)-1

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Solution for 2(m-2)=-5(3-m)-1 equation: 



2(m-2)=-5(3-m)-1

We move all terms to the left:

2(m-2)-(-5(3-m)-1)=0

We add all the numbers together, and all the variables

2(m-2)-(-5(-1m+3)-1)=0

We multiply parentheses

2m-(-5(-1m+3)-1)-4=0



We calculate terms in parentheses: -(-5(-1m+3)-1), so:

-5(-1m+3)-1

We multiply parentheses

5m-15-1

We add all the numbers together, and all the variables

5m-16

Back to the equation:

-(5m-16)



We get rid of parentheses

2m-5m+16-4=0

We add all the numbers together, and all the variables

-3m+12=0

We move all terms containing m to the left, all other terms to the right

-3m=-12

m=-12/-3

m=+4

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