2(m-3)+4=3(m-2)+2m-2

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Solution for 2(m-3)+4=3(m-2)+2m-2 equation: 



2(m-3)+4=3(m-2)+2m-2

We move all terms to the left:

2(m-3)+4-(3(m-2)+2m-2)=0

We multiply parentheses

2m-(3(m-2)+2m-2)-6+4=0



We calculate terms in parentheses: -(3(m-2)+2m-2), so:

3(m-2)+2m-2

We add all the numbers together, and all the variables

2m+3(m-2)-2

We multiply parentheses

2m+3m-6-2

We add all the numbers together, and all the variables

5m-8

Back to the equation:

-(5m-8)



We add all the numbers together, and all the variables

2m-(5m-8)-2=0

We get rid of parentheses

2m-5m+8-2=0

We add all the numbers together, and all the variables

-3m+6=0

We move all terms containing m to the left, all other terms to the right

-3m=-6

m=-6/-3

m=+2

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