2(m-3)-7(m-1)=3(6-m)

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Solution for 2(m-3)-7(m-1)=3(6-m) equation: 



2(m-3)-7(m-1)=3(6-m)

We move all terms to the left:

2(m-3)-7(m-1)-(3(6-m))=0

We add all the numbers together, and all the variables

2(m-3)-7(m-1)-(3(-1m+6))=0

We multiply parentheses

2m-7m-(3(-1m+6))-6+7=0



We calculate terms in parentheses: -(3(-1m+6)), so:

3(-1m+6)

We multiply parentheses

-3m+18

Back to the equation:

-(-3m+18)



We add all the numbers together, and all the variables

-5m-(-3m+18)+1=0

We get rid of parentheses

-5m+3m-18+1=0

We add all the numbers together, and all the variables

-2m-17=0

We move all terms containing m to the left, all other terms to the right

-2m=17

m=17/-2

m=-8+1/2

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