2(m-3)=12(6-m)

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Solution for 2(m-3)=12(6-m) equation:



2(m-3)=12(6-m)
We move all terms to the left:
2(m-3)-(12(6-m))=0
We add all the numbers together, and all the variables
2(m-3)-(12(-1m+6))=0
We multiply parentheses
2m-(12(-1m+6))-6=0
We calculate terms in parentheses: -(12(-1m+6)), so:
12(-1m+6)
We multiply parentheses
-12m+72
Back to the equation:
-(-12m+72)
We get rid of parentheses
2m+12m-72-6=0
We add all the numbers together, and all the variables
14m-78=0
We move all terms containing m to the left, all other terms to the right
14m=78
m=78/14
m=5+4/7

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