2(m-7)=4(m+4)-18

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Solution for 2(m-7)=4(m+4)-18 equation: 



2(m-7)=4(m+4)-18

We move all terms to the left:

2(m-7)-(4(m+4)-18)=0

We multiply parentheses

2m-(4(m+4)-18)-14=0



We calculate terms in parentheses: -(4(m+4)-18), so:

4(m+4)-18

We multiply parentheses

4m+16-18

We add all the numbers together, and all the variables

4m-2

Back to the equation:

-(4m-2)



We get rid of parentheses

2m-4m+2-14=0

We add all the numbers together, and all the variables

-2m-12=0

We move all terms containing m to the left, all other terms to the right

-2m=12

m=12/-2

m=-6

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