2(n+.6)+2n=2(n+.1)+2(2n)

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Solution for 2(n+.6)+2n=2(n+.1)+2(2n) equation:



2(n+.6)+2n=2(n+.1)+2(2n)
We move all terms to the left:
2(n+.6)+2n-(2(n+.1)+2(2n))=0
We add all the numbers together, and all the variables
2(n+0.6)+2n-(2(n+0.1)+22n)=0
We add all the numbers together, and all the variables
2n+2(n+0.6)-(2(n+0.1)+22n)=0
We multiply parentheses
2n+2n-(2(n+0.1)+22n)+1.2=0
We calculate terms in parentheses: -(2(n+0.1)+22n), so:
2(n+0.1)+22n
We add all the numbers together, and all the variables
22n+2(n+0.1)
We multiply parentheses
22n+2n+0.2
We add all the numbers together, and all the variables
24n+0.2
Back to the equation:
-(24n+0.2)
We add all the numbers together, and all the variables
4n-(24n+0.2)+1.2=0
We get rid of parentheses
4n-24n-0.2+1.2=0
We add all the numbers together, and all the variables
-20n+1=0
We move all terms containing n to the left, all other terms to the right
-20n=-1
n=-1/-20
n=1/20

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