2(n+1)(n+3)+4=0

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Solution for 2(n+1)(n+3)+4=0 equation: 



2(n+1)(n+3)+4=0

We multiply parentheses ..

2(+n^2+3n+n+3)+4=0

We multiply parentheses

2n^2+6n+2n+6+4=0

We add all the numbers together, and all the variables

2n^2+8n+10=0

a = 2; b = 8; c = +10;
Δ = b2-4ac
Δ = 82-4·2·10
Δ = -16
Delta is less than zero, so there is no solution for the equation

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