2(n+1)+1=(n-5)+(n-11)

Solution for 2(n+1)+1=(n-5)+(n-11) equation:

2(n+1)+1=(n-5)+(n-11)

We move all terms to the left:

2(n+1)+1-((n-5)+(n-11))=0

We multiply parentheses

2n-((n-5)+(n-11))+2+1=0


We calculate terms in parentheses: -((n-5)+(n-11)), so:

(n-5)+(n-11)

We get rid of parentheses

n+n-5-11

We add all the numbers together, and all the variables

2n-16

Back to the equation:

-(2n-16)


We add all the numbers together, and all the variables

2n-(2n-16)+3=0

We get rid of parentheses

2n-2n+16+3=0

We add all the numbers together, and all the variables

19!=0

There is no solution for this equation