2(n+1)+1=(n-5)+(n-2)

Solution for 2(n+1)+1=(n-5)+(n-2) equation:

Simplifying
2(n + 1) + 1 = (n + -5) + (n + -2)

Reorder the terms:
2(1 + n) + 1 = (n + -5) + (n + -2)
(1 * 2 + n * 2) + 1 = (n + -5) + (n + -2)
(2 + 2n) + 1 = (n + -5) + (n + -2)

Reorder the terms:
2 + 1 + 2n = (n + -5) + (n + -2)

Combine like terms: 2 + 1 = 3
3 + 2n = (n + -5) + (n + -2)

Reorder the terms:
3 + 2n = (-5 + n) + (n + -2)

Remove parenthesis around (-5 + n)
3 + 2n = -5 + n + (n + -2)

Reorder the terms:
3 + 2n = -5 + n + (-2 + n)

Remove parenthesis around (-2 + n)
3 + 2n = -5 + n + -2 + n

Reorder the terms:
3 + 2n = -5 + -2 + n + n

Combine like terms: -5 + -2 = -7
3 + 2n = -7 + n + n

Combine like terms: n + n = 2n
3 + 2n = -7 + 2n

Add '-2n' to each side of the equation.
3 + 2n + -2n = -7 + 2n + -2n

Combine like terms: 2n + -2n = 0
3 + 0 = -7 + 2n + -2n
3 = -7 + 2n + -2n

Combine like terms: 2n + -2n = 0
3 = -7 + 0
3 = -7

Solving
3 = -7

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.