2(n+1)=2(n+3)-6

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Solution for 2(n+1)=2(n+3)-6 equation: 



2(n+1)=2(n+3)-6

We move all terms to the left:

2(n+1)-(2(n+3)-6)=0

We multiply parentheses

2n-(2(n+3)-6)+2=0



We calculate terms in parentheses: -(2(n+3)-6), so:

2(n+3)-6

We multiply parentheses

2n+6-6

We add all the numbers together, and all the variables

2n

Back to the equation:

-(2n)



We add all the numbers together, and all the variables

2!=0

There is no solution for this equation

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