2(n+1)=4(n-1)

Solution for 2(n+1)=4(n-1) equation:

Simplifying
2(n + 1) = 4(n + -1)

Reorder the terms:
2(1 + n) = 4(n + -1)
(1 * 2 + n * 2) = 4(n + -1)
(2 + 2n) = 4(n + -1)

Reorder the terms:
2 + 2n = 4(-1 + n)
2 + 2n = (-1 * 4 + n * 4)
2 + 2n = (-4 + 4n)

Solving
2 + 2n = -4 + 4n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-4n' to each side of the equation.
2 + 2n + -4n = -4 + 4n + -4n

Combine like terms: 2n + -4n = -2n
2 + -2n = -4 + 4n + -4n

Combine like terms: 4n + -4n = 0
2 + -2n = -4 + 0
2 + -2n = -4

Add '-2' to each side of the equation.
2 + -2 + -2n = -4 + -2

Combine like terms: 2 + -2 = 0
0 + -2n = -4 + -2
-2n = -4 + -2

Combine like terms: -4 + -2 = -6
-2n = -6

Divide each side by '-2'.
n = 3

Simplifying
n = 3