2(n+1/3)=3/2*n+1+1/2*n-1/3

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Solution for 2(n+1/3)=3/2*n+1+1/2*n-1/3 equation: 


n in (-oo:+oo)

2*(n+1/3) = (3/2)*n+(1/2)*n-(1/3)+1 // - (3/2)*n+(1/2)*n-(1/3)+1

2*(n+1/3)-((3/2)*n)-((1/2)*n)+1/3-1 = 0

2*(n+1/3)+(-3/2)*n+(-1/2)*n+1/3-1 = 0

2*(n+1/3)+(-3*n)/2-n/2+1/3-1 = 0

(3*2^2*(n+1/3))/(2*3)+(-3*3*n)/(2*3)+(3*(-n))/(2*3)+(1*2)/(2*3)+(-1*2*3)/(2*3) = 0

3*2^2*(n+1/3)-3*3*n+3*(-n)+1*2-1*2*3 = 0

3*n-3*n-6+2+4 = 0

2-6+4 = 0

6-6 = 0

0 = 0

0/(2*3) = 0

0/(2*3) = 0 // * 2*3

0 = 0

n belongs to the empty set

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