2(n+1/3)=3/2n+1+1/2n-1/2

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Solution for 2(n+1/3)=3/2n+1+1/2n-1/2 equation: 


n in (-oo:+oo)

2*(n+1/3) = (3/2)*n+(1/2)*n-(1/2)+1 // - (3/2)*n+(1/2)*n-(1/2)+1

2*(n+1/3)-((3/2)*n)-((1/2)*n)+1/2-1 = 0

2*(n+1/3)+(-3/2)*n+(-1/2)*n+1/2-1 = 0

2*(n+1/3)+(-3*n)/2-n/2+1/2-1 = 0

(2^2*(n+1/3))/2+(-3*n)/2-n/2+1/2+(-1*2)/2 = 0

2^2*(n+1/3)-3*n-n-1*2+1 = 0

n-n-2+1+4/3 = 0

1-2+4/3 = 0

7/3-2 = 0

1/3 = 0

1/3/2 = 0

1/3/2 = 0 // * 2

1/3 = 0

n belongs to the empty set

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