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n in (-oo:+oo)
2*(n+1/3) = (3/2)*n+(1/2)*n-(1/3)+1 // - (3/2)*n+(1/2)*n-(1/3)+1
2*(n+1/3)-((3/2)*n)-((1/2)*n)+1/3-1 = 0
2*(n+1/3)+(-3/2)*n+(-1/2)*n+1/3-1 = 0
2*(n+1/3)+(-3*n)/2-n/2+1/3-1 = 0
(3*2^2*(n+1/3))/(2*3)+(-3*3*n)/(2*3)+(3*(-n))/(2*3)+(1*2)/(2*3)+(-1*2*3)/(2*3) = 0
3*2^2*(n+1/3)-3*3*n+3*(-n)+1*2-1*2*3 = 0
3*n-3*n-6+2+4 = 0
2-6+4 = 0
6-6 = 0
0 = 0
0/(2*3) = 0
0/(2*3) = 0 // * 2*3
0 = 0
n belongs to the empty set
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