2(n+16)(2n-1)=0

Solution for 2(n+16)(2n-1)=0 equation:

2(n+16)(2n-1)=0

We multiply parentheses ..

2(+2n^2-1n+32n-16)=0

We multiply parentheses

4n^2-2n+64n-32=0

We add all the numbers together, and all the variables

4n^2+62n-32=0

a = 4; b = 62; c = -32;
Δ = b2-4ac
Δ = 622-4·4·(-32)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4356}=66$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(62)-66}{2*4}=\frac{-128}{8}
=-16
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(62)+66}{2*4}=\frac{4}{8}
=1/2
$