2(n+2)-8(8+7n)=48

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Solution for 2(n+2)-8(8+7n)=48 equation:



2(n+2)-8(8+7n)=48
We move all terms to the left:
2(n+2)-8(8+7n)-(48)=0
We add all the numbers together, and all the variables
2(n+2)-8(7n+8)-48=0
We multiply parentheses
2n-56n+4-64-48=0
We add all the numbers together, and all the variables
-54n-108=0
We move all terms containing n to the left, all other terms to the right
-54n=108
n=108/-54
n=-2

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