2(n+2)-8(8+7n)=48

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Solution for 2(n+2)-8(8+7n)=48 equation: 



2(n+2)-8(8+7n)=48

We move all terms to the left:

2(n+2)-8(8+7n)-(48)=0

We add all the numbers together, and all the variables

2(n+2)-8(7n+8)-48=0

We multiply parentheses

2n-56n+4-64-48=0

We add all the numbers together, and all the variables

-54n-108=0

We move all terms containing n to the left, all other terms to the right

-54n=108

n=108/-54

n=-2

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