2(n+2)=-(1-n)

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Solution for 2(n+2)=-(1-n) equation: 



2(n+2)=-(1-n)

We move all terms to the left:

2(n+2)-(-(1-n))=0

We add all the numbers together, and all the variables

2(n+2)-(-(-1n+1))=0

We multiply parentheses

2n-(-(-1n+1))+4=0



We calculate terms in parentheses: -(-(-1n+1)), so:

-(-1n+1)

We get rid of parentheses

1n-1

We add all the numbers together, and all the variables

n-1

Back to the equation:

-(n-1)



We get rid of parentheses

2n-n+1+4=0

We add all the numbers together, and all the variables

n+5=0

We move all terms containing n to the left, all other terms to the right

n=-5

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