2(n+2)=3(n-4)

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Solution for 2(n+2)=3(n-4) equation: 



2(n+2)=3(n-4)

We move all terms to the left:

2(n+2)-(3(n-4))=0

We multiply parentheses

2n-(3(n-4))+4=0



We calculate terms in parentheses: -(3(n-4)), so:

3(n-4)

We multiply parentheses

3n-12

Back to the equation:

-(3n-12)



We get rid of parentheses

2n-3n+12+4=0

We add all the numbers together, and all the variables

-1n+16=0

We move all terms containing n to the left, all other terms to the right

-n=-16

n=-16/-1

n=+16

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