2(n+2)=3(n-8)

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Solution for 2(n+2)=3(n-8) equation: 



2(n+2)=3(n-8)

We move all terms to the left:

2(n+2)-(3(n-8))=0

We multiply parentheses

2n-(3(n-8))+4=0



We calculate terms in parentheses: -(3(n-8)), so:

3(n-8)

We multiply parentheses

3n-24

Back to the equation:

-(3n-24)



We get rid of parentheses

2n-3n+24+4=0

We add all the numbers together, and all the variables

-1n+28=0

We move all terms containing n to the left, all other terms to the right

-n=-28

n=-28/-1

n=+28

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