2(n+2)=6+4n

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Solution for 2(n+2)=6+4n equation: 



2(n+2)=6+4n

We move all terms to the left:

2(n+2)-(6+4n)=0

We add all the numbers together, and all the variables

2(n+2)-(4n+6)=0

We multiply parentheses

2n-(4n+6)+4=0

We get rid of parentheses

2n-4n-6+4=0

We add all the numbers together, and all the variables

-2n-2=0

We move all terms containing n to the left, all other terms to the right

-2n=2

n=2/-2

n=-1

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