2(n+3)+3(n+1)=42

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Solution for 2(n+3)+3(n+1)=42 equation: 



2(n+3)+3(n+1)=42

We move all terms to the left:

2(n+3)+3(n+1)-(42)=0

We multiply parentheses

2n+3n+6+3-42=0

We add all the numbers together, and all the variables

5n-33=0

We move all terms containing n to the left, all other terms to the right

5n=33

n=33/5

n=6+3/5

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