2(n+3)-n=-n-4(n+2)

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Solution for 2(n+3)-n=-n-4(n+2) equation: 



2(n+3)-n=-n-4(n+2)

We move all terms to the left:

2(n+3)-n-(-n-4(n+2))=0

We add all the numbers together, and all the variables

-1n+2(n+3)-(-n-4(n+2))=0

We multiply parentheses

-1n+2n-(-n-4(n+2))+6=0



We calculate terms in parentheses: -(-n-4(n+2)), so:

-n-4(n+2)

We add all the numbers together, and all the variables

-1n-4(n+2)

We multiply parentheses

-1n-4n-8

We add all the numbers together, and all the variables

-5n-8

Back to the equation:

-(-5n-8)



We add all the numbers together, and all the variables

n-(-5n-8)+6=0

We get rid of parentheses

n+5n+8+6=0

We add all the numbers together, and all the variables

6n+14=0

We move all terms containing n to the left, all other terms to the right

6n=-14

n=-14/6

n=-2+1/3

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