2(n+3)=4(n-8)

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Solution for 2(n+3)=4(n-8) equation: 



2(n+3)=4(n-8)

We move all terms to the left:

2(n+3)-(4(n-8))=0

We multiply parentheses

2n-(4(n-8))+6=0



We calculate terms in parentheses: -(4(n-8)), so:

4(n-8)

We multiply parentheses

4n-32

Back to the equation:

-(4n-32)



We get rid of parentheses

2n-4n+32+6=0

We add all the numbers together, and all the variables

-2n+38=0

We move all terms containing n to the left, all other terms to the right

-2n=-38

n=-38/-2

n=+19

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