2(n+4)=8-n

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Solution for 2(n+4)=8-n equation: 



2(n+4)=8-n

We move all terms to the left:

2(n+4)-(8-n)=0

We add all the numbers together, and all the variables

2(n+4)-(-1n+8)=0

We multiply parentheses

2n-(-1n+8)+8=0

We get rid of parentheses

2n+1n-8+8=0

We add all the numbers together, and all the variables

3n=0

n=0/3

n=0

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