2(n+5)+3(n-2)=4(n-1)+3(n+4)

Solution for 2(n+5)+3(n-2)=4(n-1)+3(n+4) equation:

2(n+5)+3(n-2)=4(n-1)+3(n+4)

We move all terms to the left:

2(n+5)+3(n-2)-(4(n-1)+3(n+4))=0

We multiply parentheses

2n+3n-(4(n-1)+3(n+4))+10-6=0


We calculate terms in parentheses: -(4(n-1)+3(n+4)), so:

4(n-1)+3(n+4)

We multiply parentheses

4n+3n-4+12

We add all the numbers together, and all the variables

7n+8

Back to the equation:

-(7n+8)


We add all the numbers together, and all the variables

5n-(7n+8)+4=0

We get rid of parentheses

5n-7n-8+4=0

We add all the numbers together, and all the variables

-2n-4=0

We move all terms containing n to the left, all other terms to the right

-2n=4

n=4/-2

n=-2