2(n-1)+4=(3n-1)

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Solution for 2(n-1)+4=(3n-1) equation: 


Simplifying
2(n + -1) + 4 = (3n + -1)

Reorder the terms:
2(-1 + n) + 4 = (3n + -1)
(-1 * 2 + n * 2) + 4 = (3n + -1)
(-2 + 2n) + 4 = (3n + -1)

Reorder the terms:
-2 + 4 + 2n = (3n + -1)

Combine like terms: -2 + 4 = 2
2 + 2n = (3n + -1)

Reorder the terms:
2 + 2n = (-1 + 3n)

Remove parenthesis around (-1 + 3n)
2 + 2n = -1 + 3n

Solving
2 + 2n = -1 + 3n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-3n' to each side of the equation.
2 + 2n + -3n = -1 + 3n + -3n

Combine like terms: 2n + -3n = -1n
2 + -1n = -1 + 3n + -3n

Combine like terms: 3n + -3n = 0
2 + -1n = -1 + 0
2 + -1n = -1

Add '-2' to each side of the equation.
2 + -2 + -1n = -1 + -2

Combine like terms: 2 + -2 = 0
0 + -1n = -1 + -2
-1n = -1 + -2

Combine like terms: -1 + -2 = -3
-1n = -3

Divide each side by '-1'.
n = 3

Simplifying
n = 3

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