2(n-1)+4n=2(3n-1)

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Solution for 2(n-1)+4n=2(3n-1) equation:


Simplifying
2(n + -1) + 4n = 2(3n + -1)

Reorder the terms:
2(-1 + n) + 4n = 2(3n + -1)
(-1 * 2 + n * 2) + 4n = 2(3n + -1)
(-2 + 2n) + 4n = 2(3n + -1)

Combine like terms: 2n + 4n = 6n
-2 + 6n = 2(3n + -1)

Reorder the terms:
-2 + 6n = 2(-1 + 3n)
-2 + 6n = (-1 * 2 + 3n * 2)
-2 + 6n = (-2 + 6n)

Add '2' to each side of the equation.
-2 + 2 + 6n = -2 + 2 + 6n

Combine like terms: -2 + 2 = 0
0 + 6n = -2 + 2 + 6n
6n = -2 + 2 + 6n

Combine like terms: -2 + 2 = 0
6n = 0 + 6n
6n = 6n

Add '-6n' to each side of the equation.
6n + -6n = 6n + -6n

Combine like terms: 6n + -6n = 0
0 = 6n + -6n

Combine like terms: 6n + -6n = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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