2(n-1)+4n=2(3n-10)

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Solution for 2(n-1)+4n=2(3n-10) equation: 



2(n-1)+4n=2(3n-10)

We move all terms to the left:

2(n-1)+4n-(2(3n-10))=0

We add all the numbers together, and all the variables

4n+2(n-1)-(2(3n-10))=0

We multiply parentheses

4n+2n-(2(3n-10))-2=0



We calculate terms in parentheses: -(2(3n-10)), so:

2(3n-10)

We multiply parentheses

6n-20

Back to the equation:

-(6n-20)



We add all the numbers together, and all the variables

6n-(6n-20)-2=0

We get rid of parentheses

6n-6n+20-2=0

We add all the numbers together, and all the variables

18!=0

There is no solution for this equation

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