2(n-1)+4n=2(3n-2

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Solution for 2(n-1)+4n=2(3n-2 equation: 



2(n-1)+4n=2(3n-2

We move all terms to the left:

2(n-1)+4n-(2(3n-2)=0

We add all the numbers together, and all the variables

4n+2(n-1)-(2(3n-2)=0

We multiply parentheses

4n+2n-(2(3n-2)-2=0

We add all the numbers together, and all the variables

6n-(2(3n-2)-2=0

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