2(n-1)+4n=s(3n-1)

Solution for 2(n-1)+4n=s(3n-1) equation:

Simplifying
2(n + -1) + 4n = s(3n + -1)

Reorder the terms:
2(-1 + n) + 4n = s(3n + -1)
(-1 * 2 + n * 2) + 4n = s(3n + -1)
(-2 + 2n) + 4n = s(3n + -1)

Combine like terms: 2n + 4n = 6n
-2 + 6n = s(3n + -1)

Reorder the terms:
-2 + 6n = s(-1 + 3n)
-2 + 6n = (-1 * s + 3n * s)

Reorder the terms:
-2 + 6n = (3ns + -1s)
-2 + 6n = (3ns + -1s)

Solving
-2 + 6n = 3ns + -1s

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-3ns' to each side of the equation.
-2 + 6n + -3ns = 3ns + -3ns + -1s

Combine like terms: 3ns + -3ns = 0
-2 + 6n + -3ns = 0 + -1s
-2 + 6n + -3ns = -1s

Add '2' to each side of the equation.
-2 + 6n + 2 + -3ns = 2 + -1s

Reorder the terms:
-2 + 2 + 6n + -3ns = 2 + -1s

Combine like terms: -2 + 2 = 0
0 + 6n + -3ns = 2 + -1s
6n + -3ns = 2 + -1s

Reorder the terms:
-2 + 6n + -3ns + s = 2 + -1s + -2 + s

Reorder the terms:
-2 + 6n + -3ns + s = 2 + -2 + -1s + s

Combine like terms: 2 + -2 = 0
-2 + 6n + -3ns + s = 0 + -1s + s
-2 + 6n + -3ns + s = -1s + s

Combine like terms: -1s + s = 0
-2 + 6n + -3ns + s = 0

The solution to this equation could not be determined.