2(n-1)-5=2(1-n)-1

Solution for 2(n-1)-5=2(1-n)-1 equation:

2(n-1)-5=2(1-n)-1

We move all terms to the left:

2(n-1)-5-(2(1-n)-1)=0

We add all the numbers together, and all the variables

2(n-1)-(2(-1n+1)-1)-5=0

We multiply parentheses

2n-(2(-1n+1)-1)-2-5=0


We calculate terms in parentheses: -(2(-1n+1)-1), so:

2(-1n+1)-1

We multiply parentheses

-2n+2-1

We add all the numbers together, and all the variables

-2n+1

Back to the equation:

-(-2n+1)


We add all the numbers together, and all the variables

2n-(-2n+1)-7=0

We get rid of parentheses

2n+2n-1-7=0

We add all the numbers together, and all the variables

4n-8=0

We move all terms containing n to the left, all other terms to the right

4n=8

n=8/4

n=2