2(n-1)=3n-33

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Solution for 2(n-1)=3n-33 equation: 



2(n-1)=3n-33

We move all terms to the left:

2(n-1)-(3n-33)=0

We multiply parentheses

2n-(3n-33)-2=0

We get rid of parentheses

2n-3n+33-2=0

We add all the numbers together, and all the variables

-1n+31=0

We move all terms containing n to the left, all other terms to the right

-n=-31

n=-31/-1

n=+31

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