2(n-1)=4(n+2)

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Solution for 2(n-1)=4(n+2) equation: 



2(n-1)=4(n+2)

We move all terms to the left:

2(n-1)-(4(n+2))=0

We multiply parentheses

2n-(4(n+2))-2=0



We calculate terms in parentheses: -(4(n+2)), so:

4(n+2)

We multiply parentheses

4n+8

Back to the equation:

-(4n+8)



We get rid of parentheses

2n-4n-8-2=0

We add all the numbers together, and all the variables

-2n-10=0

We move all terms containing n to the left, all other terms to the right

-2n=10

n=10/-2

n=-5

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