2(n-2)-(3+5n)=-4n

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Solution for 2(n-2)-(3+5n)=-4n equation: 



2(n-2)-(3+5n)=-4n

We move all terms to the left:

2(n-2)-(3+5n)-(-4n)=0

We add all the numbers together, and all the variables

2(n-2)-(5n+3)-(-4n)=0

We multiply parentheses

2n-(5n+3)-(-4n)-4=0

We get rid of parentheses

2n-5n+4n-3-4=0

We add all the numbers together, and all the variables

n-7=0

We move all terms containing n to the left, all other terms to the right

n=7

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