2(n-2)-4=2(n-3)

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Solution for 2(n-2)-4=2(n-3) equation: 



2(n-2)-4=2(n-3)

We move all terms to the left:

2(n-2)-4-(2(n-3))=0

We multiply parentheses

2n-(2(n-3))-4-4=0



We calculate terms in parentheses: -(2(n-3)), so:

2(n-3)

We multiply parentheses

2n-6

Back to the equation:

-(2n-6)



We add all the numbers together, and all the variables

2n-(2n-6)-8=0

We get rid of parentheses

2n-2n+6-8=0

We add all the numbers together, and all the variables

-2!=0

There is no solution for this equation

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