2(n-3)+(n+1)=40

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Solution for 2(n-3)+(n+1)=40 equation:


Simplifying
2(n + -3) + (n + 1) = 40

Reorder the terms:
2(-3 + n) + (n + 1) = 40
(-3 * 2 + n * 2) + (n + 1) = 40
(-6 + 2n) + (n + 1) = 40

Reorder the terms:
-6 + 2n + (1 + n) = 40

Remove parenthesis around (1 + n)
-6 + 2n + 1 + n = 40

Reorder the terms:
-6 + 1 + 2n + n = 40

Combine like terms: -6 + 1 = -5
-5 + 2n + n = 40

Combine like terms: 2n + n = 3n
-5 + 3n = 40

Solving
-5 + 3n = 40

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + 3n = 40 + 5

Combine like terms: -5 + 5 = 0
0 + 3n = 40 + 5
3n = 40 + 5

Combine like terms: 40 + 5 = 45
3n = 45

Divide each side by '3'.
n = 15

Simplifying
n = 15

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