2(n-3)+4n+6n+1=1

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Solution for 2(n-3)+4n+6n+1=1 equation: 



2(n-3)+4n+6n+1=1

We move all terms to the left:

2(n-3)+4n+6n+1-(1)=0

We add all the numbers together, and all the variables

10n+2(n-3)=0

We multiply parentheses

10n+2n-6=0

We add all the numbers together, and all the variables

12n-6=0

We move all terms containing n to the left, all other terms to the right

12n=6

n=6/12

n=1/2

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