2(n-3)+4n+6n+1=12n-5

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Solution for 2(n-3)+4n+6n+1=12n-5 equation: 



2(n-3)+4n+6n+1=12n-5

We move all terms to the left:

2(n-3)+4n+6n+1-(12n-5)=0

We add all the numbers together, and all the variables

10n+2(n-3)-(12n-5)+1=0

We multiply parentheses

10n+2n-(12n-5)-6+1=0

We get rid of parentheses

10n+2n-12n+5-6+1=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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