2(n-3)+5=(n-1)

Solution for 2(n-3)+5=(n-1) equation:

Simplifying
2(n + -3) + 5 = (n + -1)

Reorder the terms:
2(-3 + n) + 5 = (n + -1)
(-3 * 2 + n * 2) + 5 = (n + -1)
(-6 + 2n) + 5 = (n + -1)

Reorder the terms:
-6 + 5 + 2n = (n + -1)

Combine like terms: -6 + 5 = -1
-1 + 2n = (n + -1)

Reorder the terms:
-1 + 2n = (-1 + n)

Remove parenthesis around (-1 + n)
-1 + 2n = -1 + n

Add '1' to each side of the equation.
-1 + 1 + 2n = -1 + 1 + n

Combine like terms: -1 + 1 = 0
0 + 2n = -1 + 1 + n
2n = -1 + 1 + n

Combine like terms: -1 + 1 = 0
2n = 0 + n
2n = n

Solving
2n = n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-1n' to each side of the equation.
2n + -1n = n + -1n

Combine like terms: 2n + -1n = 1n
1n = n + -1n

Combine like terms: n + -1n = 0
1n = 0

Divide each side by '1'.
n = 0

Simplifying
n = 0