2(n-3)+7=3(n-1)

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Solution for 2(n-3)+7=3(n-1) equation:


Simplifying
2(n + -3) + 7 = 3(n + -1)

Reorder the terms:
2(-3 + n) + 7 = 3(n + -1)
(-3 * 2 + n * 2) + 7 = 3(n + -1)
(-6 + 2n) + 7 = 3(n + -1)

Reorder the terms:
-6 + 7 + 2n = 3(n + -1)

Combine like terms: -6 + 7 = 1
1 + 2n = 3(n + -1)

Reorder the terms:
1 + 2n = 3(-1 + n)
1 + 2n = (-1 * 3 + n * 3)
1 + 2n = (-3 + 3n)

Solving
1 + 2n = -3 + 3n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-3n' to each side of the equation.
1 + 2n + -3n = -3 + 3n + -3n

Combine like terms: 2n + -3n = -1n
1 + -1n = -3 + 3n + -3n

Combine like terms: 3n + -3n = 0
1 + -1n = -3 + 0
1 + -1n = -3

Add '-1' to each side of the equation.
1 + -1 + -1n = -3 + -1

Combine like terms: 1 + -1 = 0
0 + -1n = -3 + -1
-1n = -3 + -1

Combine like terms: -3 + -1 = -4
-1n = -4

Divide each side by '-1'.
n = 4

Simplifying
n = 4

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