2(n-3)-5(n-7)=0

Solution for 2(n-3)-5(n-7)=0 equation:

Simplifying
2(n + -3) + -5(n + -7) = 0

Reorder the terms:
2(-3 + n) + -5(n + -7) = 0
(-3 * 2 + n * 2) + -5(n + -7) = 0
(-6 + 2n) + -5(n + -7) = 0

Reorder the terms:
-6 + 2n + -5(-7 + n) = 0
-6 + 2n + (-7 * -5 + n * -5) = 0
-6 + 2n + (35 + -5n) = 0

Reorder the terms:
-6 + 35 + 2n + -5n = 0

Combine like terms: -6 + 35 = 29
29 + 2n + -5n = 0

Combine like terms: 2n + -5n = -3n
29 + -3n = 0

Solving
29 + -3n = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-29' to each side of the equation.
29 + -29 + -3n = 0 + -29

Combine like terms: 29 + -29 = 0
0 + -3n = 0 + -29
-3n = 0 + -29

Combine like terms: 0 + -29 = -29
-3n = -29

Divide each side by '-3'.
n = 9.666666667

Simplifying
n = 9.666666667