2(n-3)=1/4(d-2)

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Solution for 2(n-3)=1/4(d-2) equation: 


x in (-oo:+oo)

2*(n-3) = (1/4)*(d-2) // - (1/4)*(d-2)

2*(n-3)-((1/4)*(d-2)) = 0

2*(n-3)+(-1/4)*(d-2) = 0

2*(n-3)-1/4*(d-2) = 0

2*(n-3)-1/4*(d-2) = 0

2*n-1/4*d-11/2 = 0

2*n-1/4*d-11/2 = 0

x belongs to the empty set

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