2(n-3)=3(n-1)

Solution for 2(n-3)=3(n-1) equation:

Simplifying
2(n + -3) = 3(n + -1)

Reorder the terms:
2(-3 + n) = 3(n + -1)
(-3 * 2 + n * 2) = 3(n + -1)
(-6 + 2n) = 3(n + -1)

Reorder the terms:
-6 + 2n = 3(-1 + n)
-6 + 2n = (-1 * 3 + n * 3)
-6 + 2n = (-3 + 3n)

Solving
-6 + 2n = -3 + 3n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-3n' to each side of the equation.
-6 + 2n + -3n = -3 + 3n + -3n

Combine like terms: 2n + -3n = -1n
-6 + -1n = -3 + 3n + -3n

Combine like terms: 3n + -3n = 0
-6 + -1n = -3 + 0
-6 + -1n = -3

Add '6' to each side of the equation.
-6 + 6 + -1n = -3 + 6

Combine like terms: -6 + 6 = 0
0 + -1n = -3 + 6
-1n = -3 + 6

Combine like terms: -3 + 6 = 3
-1n = 3

Divide each side by '-1'.
n = -3

Simplifying
n = -3