2(n-3)=3(z+2)

Solution for 2(n-3)=3(z+2) equation:

Simplifying
2(n + -3) = 3(z + 2)

Reorder the terms:
2(-3 + n) = 3(z + 2)
(-3 * 2 + n * 2) = 3(z + 2)
(-6 + 2n) = 3(z + 2)

Reorder the terms:
-6 + 2n = 3(2 + z)
-6 + 2n = (2 * 3 + z * 3)
-6 + 2n = (6 + 3z)

Solving
-6 + 2n = 6 + 3z

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + 2n = 6 + 6 + 3z

Combine like terms: -6 + 6 = 0
0 + 2n = 6 + 6 + 3z
2n = 6 + 6 + 3z

Combine like terms: 6 + 6 = 12
2n = 12 + 3z

Divide each side by '2'.
n = 6 + 1.5z

Simplifying
n = 6 + 1.5z