2(n-3)=4,n+1

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Solution for 2(n-3)=4,n+1 equation: 



2(n-3)=4.n+1

We move all terms to the left:

2(n-3)-(4.n+1)=0

We multiply parentheses

2n-(4.n+1)-6=0

We get rid of parentheses

2n-4.n-1-6=0

We add all the numbers together, and all the variables

-2n-7=0

We move all terms containing n to the left, all other terms to the right

-2n=7

n=7/-2

n=-3+1/2

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