2(n-3)=n+4n+1

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Solution for 2(n-3)=n+4n+1 equation: 



2(n-3)=n+4n+1

We move all terms to the left:

2(n-3)-(n+4n+1)=0

We add all the numbers together, and all the variables

2(n-3)-(5n+1)=0

We multiply parentheses

2n-(5n+1)-6=0

We get rid of parentheses

2n-5n-1-6=0

We add all the numbers together, and all the variables

-3n-7=0

We move all terms containing n to the left, all other terms to the right

-3n=7

n=7/-3

n=-2+1/3

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